Physics, asked by Kaushalsingh74883508, 1 day ago

The horizontal range of a projectile fired at an angle of 15° is 50 m. If it is fired with the same speed at an angle of 45°, its range will be
(a) 60 m (b) 71m (c) 100 m (d) 141m​

Answers

Answered by itsrishab31
3

✮\huge{❥}\:᭄{\mathtt{{\purple{\boxed{\tt{\pink{\red{A}\pink{n}\orange{s}\green{w}\blue{e}\purple{r᭄}}}}}}}}❥✮

Correct option is { C } 100 m

The horizontal range of a projectile fixed at an angle=15°

Range=50m

In dirst case range=50=u2/g(sin2×15°)

50=2g2gu2=100

In 2nd case range=g(sin2×45°)u2=1100(∵sin90°=1)=100m

Answered by TGMRohit
1

Answer:

hai myself rohit

Explanation:

how are you xd..

can I get yr intro

Similar questions