The horizontal range of a projectile fired at an angle of 15° is 50 m. If it is fired with the same speed at an angle of 45°, its range will be
(a) 60 m (b) 71m (c) 100 m (d) 141m
Answers
Answered by
3
Correct option is { C } 100 m
The horizontal range of a projectile fixed at an angle=15°
Range=50m
In dirst case range=50=u2/g(sin2×15°)
50=2g2gu2=100
In 2nd case range=g(sin2×45°)u2=1100(∵sin90°=1)=100m
Answered by
1
Answer:
hai myself rohit
Explanation:
how are you xd..
can I get yr intro
Similar questions