Question

The horizontal range of a projectile is 4√3 times of its maximum height. The angle of projection Will be

Answer 1

Answer:

Using fórmula of range and maximum height

We get

H/R = tan(θ)/4

Given R = 4√3*H

1/(4√3) = tan(θ)/4

1/√3 = tan(θ)

θ = arctan(1/√3) = 30°

The angle of projection is 30°