Question

The horizontal range of a projectile is 4√3 times
of its maximum height. Calculate the angle of
projection.​

Answer 1

Explanation:

The horizontal range of a projectile is 4√3 times

of its maximum height. Calculate the angle of

projection.

Answer 2

Explanation:

Let Velocity is V and angle of projection with horizontal is θ.

∴Range=

g

2V

2

sinθcosθ

∴Maximum Height=

2g

V

2

sin

2

θ

According to given condition, Range =4

3

Height

⇒

g

2V

2

sinθcosθ

=4

3

2g

V

2

sin

2

θ

⇒tanθ=

3

1

⇒θ=30

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