Question

The horizontal range of a projectile is 4 root 2 times its
maximum height. Its angle of projection will be​

Answer 1

Answer:

Given: Horizontal range = 4√2 times of Maximum height.

To find : Angle of projection

Formulas used:

1. Range = u²[sin(2θ)/g]

2. Maximum height = u²[sin²(θ)/2g]

3. sin(2θ) = 2sin(θ)cos(θ)

Calculation:

Range = 4√2 Max height

=>u²[sin(2θ)/g ]= (4√2)× u²[sin²(θ)/2g]

=> 2 sin (θ)cos(θ) =(4√2) sin²(θ)/2

=> tan(θ) = 1/√2

=> (θ) = tan ^(-1)[(1/√2)].

tan ^(-1) refers to tan inverse