Question

The horizontal range of a projectile projected from ground is maximum. The angle of projection from vertical is
1) 0
2) 45°
3) 90°
3) 30°​

Answer 1

Answer:

2) 45°

When an object is projected at an angle of 45° to the horizontal,it covers more range as compared to when projected through any other angle.

Explanation :-

Range of a projectile projected at an angle $\theta$ is given by :-

R = $\boxed{\dfrac{u^2sin2\theta}{g}}$

• Now, R will be maximum when $sin2\theta$ will be maximum.

• Maximum value of sin is attained at an angle of $\dfrac{\pi}{2}$.

• Therefore, $sin2\theta$ will be maximum at $2\theta \:=\: \dfrac{\pi}{2}$ which gives $\theta \:=\: \dfrac{\pi}{4}$.

• $\dfrac{\pi}{4} \:=\: 45\degree$.