Question

The horizontal range of Shell fired with speed of 49m/s at an angle 15 , then what is horizontal range ??
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Answer 1

Explanation:

If a shell is projected with an initial velocity of

u

at an angle

θ

w.r.t to the horizontal,

It's range is given by the formula

u

2

sin

2

θ

g

Total time of flight as

2

u

sin

θ

g

And,maximum height as

(

u

sin

θ

)

2

2

g

Now,given,

u

=

392

m

s

and

θ

=

30

So,putting the values we get,

Total time of flight =

39.96

s

Range =

13565

m

Maximum height reached =

1958

m