Question

The hormonics which are presnt in the pipe open at both ends are

Answer 1

Answer:

An open pipe has an antinode at either end.

The first harmonic or fundamental wavelength is then

L = y / 2   where L is the length of the pipe and y is the wavelength.

The length of the pipe will be an integral number of half-wavelenths.

Or   L = y  / 2 for the first harmonic

       L = y  for the second harmonic

       L = 3 y  / 2    for the third harmonic, etc.

        so L = n y  / 2

The corresponding frequencies are then

       f = v / y   where v is the speed of sound

  then f1 = v / (2 L)

           f2 = v / L

            f3 = 3 v / (2 (L)    etc.