Question

the horziontal range for a projection is maximum when the angle of projection is a)0° b)90° c)45° d)30°​

Answer 1

Explanation:

Let Velocity is V and the angle of projection with horizontal is θ.

∴Range, R=

g

2V

2

sinθcosθ

=

g

V

2

sin2θ

⇒

dθ

dR

=

g

V

2

2cos2θ=0 ⇒2θ=90

o

⇒θ=45

o

⇒

dθ

2

d

2

R

=−

g

V

2

4sin2θ, at θ=45

o

⇒

dθ

2

d

2

R

=−

g

4V

2

<0

Hence, at θ=45

o

, Range is maximum

Answer 2

Answer:

45°

option C

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