Question

The hot iron ball at 250°C is cooled by placing in air which is at 100°C. The diameter of
iron ball is 4 cm. The internal resistance is neglected. After 10 min what is the temperature
of the iron ball?
Data:
kg
p=1500
J
C, = 300
kg - °C
W
h = 5​

Answer 1

Answer:

hope it's helpful

Explanation:

B = 0.1

Latent heat of fusion is 336 J/g.

Latent heat of vaporization is 2260 J/g.

Balancing the heat, mcΔT=L×mice

⇒0.2×100×C=336×103×25×10−3

⇒C=420J/kgoC=0.1cal/goC