THE HOUR HAND OF A CIRCULAR CLOCK IS 14 CM LONG.
HOW MUCH DISTANCE WILL ITS OUTER TIP COVER IN 3 DAYS ?
please answer in detail
Answers
Answered by
34
radius = 14 cm
circumference= distance covered in 12 hours = 2*22/7*14= 88cm
in three days
no. of hours = 3*24= 72
no. of 12 hours = 72/12= 6.
distance covered in 3 days = 88*6= 528
circumference= distance covered in 12 hours = 2*22/7*14= 88cm
in three days
no. of hours = 3*24= 72
no. of 12 hours = 72/12= 6.
distance covered in 3 days = 88*6= 528
Answered by
3
Given: Hour hand = 14 cm long
To find: Distance outer tip will cover in 3 days
Radius of clock (r) = 14 cm
Circumference = 2πr (Distance covered in 12 hours)
= 2 × 22 × 14
7
= 88 cm
Now by using Unitary method,
No. of hours in 3 days= 3 × 24
= 72
No. of 12 hours = 72
12
= 6
Distance covered in 3 days = 88 × 6
= 528 cm
So 528 cm distance will be covered by its outer tip in 3 Days.
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