Question

the hour hand of a clock is 6.3 cm long .find the distance covered by it in 2 days.

Answer 1

heya

here is ur answer

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Given :-

length of hour hand = radius = 6.3 cm

♦ we all know that 1 hour is equal to one rotation.

SO

♦ first let us find area swept with in a hour

♦ area swept = circumference of circle = 2πr

✒ 2 × 22/7 × 6.3

✒ 2×22×0.9

✒44× 0.9

✒ 39.6

♦ so v had found the area swept in 1 hour ,but in question ,it's given 2 hours

♦ let's find it

✴ one day = 24 hours ➡ 2 days = 2×24= 48 hours.

✴ 1 hour = 39.6

✴ 48 hours = ?

✴ 48 hours = 48 × 39.6 = 1900.8

_________

area swept in 2 days = 1900.8 cm^2


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hope it helps u.!!

thnkq

Answer 2

Answer: 1900.8 cm square

Step-by-step explanation:

Given :-

length of hour hand = radius = 6.3 cm

♦ we all know that 1 hour is equal to one rotation.

SO

♦ first let us find area swept with in a hour

♦ area swept = circumference of circle = 2πr

✒ 2 × 22/7 × 6.3

✒ 2×22×0.9

✒44× 0.9

✒ 39.6

♦ so v had found the area swept in 1 hour ,but in question ,it's given 2 hours

♦ let's find it

✴ one day = 24 hours ➡ 2 days = 2×24= 48 hours.

✴ 1 hour = 39.6

✴ 48 hours = ?

✴ 48 hours = 48 × 39.6 = 1900.8

_________

area swept in 2 days = 1900.8 cm^2