Question

The hour hand of a clock is 6 cm long. The area swept by it between 11.20 am and 11.55 am is
(a)2.75 cm²
(b)5.5 cm²
(c)11 cm²
(d)10 cm²

Answer 1

Answer:

The angle described by the hour hand on the face of the clock between 11:20 AM and 11:55 AM is 5.5 cm²

Among the given options option (b) 5.5 cm²  is the correct answer.

Step-by-step explanation:

Given :

Radius of circle(clock),r = 6 cm

Minutes between 11:20 AM and 11:55 AM = 35 min  

Angle described by the hour hand in one minute = 1/60 ×30° = 1/2°

Angle described by the hour hand in 5 minutes ,θ = 1/2° × 35 = 17.5°

Angle swept by the hour hand in 35 minutes = Area of sector of angle 17.5° in a circle of radius 6 cm

Area of the sector of a circle, A = (θ/360) × πr²

A = (17.5°/360°) × π ×6²

A = 17.5/10  × 22/7  

A = (17.5 × 22)/70

A = 385/70

A = 5.5 cm²

Angle described by the hour hand in 35 minutes , A = 5.5 cm²

Hence, the angle described by the hour hand on the face of the clock between 11:20 AM and 11:55 AM is 5.5 cm²

HOPE THIS ANSWER WILL HELP YOU….

Answer 2

Hey mate..

Here is ur answer

option B

5.5cm^2

hope it's helpful