The houses in a row are numbered consecutively from 1 to 49.Show that there exist a value of X such that sum of numbers of houses preceeding the house numbered X is equal to sum of the umbers of houses following X. Find value of X.
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here's your answer, HOPE IT HELPS !!!!!!!!!!!
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devis2awesome:
I was kind of hoping the solution would be in regards with AP but nice try
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Row houses are numbers from 1,2,3,4,5…….49.
Thus we can see the houses numbered in a row are in the form of AP.
So,
First term, a = 1
Common difference, d=1
Let us say the number of xth houses can be represented as;
Sum of preceding the numbers of x = sum of following numbers of x
i.e. Sum of ( 1,2,3,….x-1) = sum of [(x+1), (x+2) ,….48,49]
That is 1 + 2 + 3 + …… + ( x-1) = ( x+1) + ( x+2) …… + 49
Therefore, the value of x is 35
Hope it's Helpful.....:)
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