the houses in a row are numbered consequently from 1 to 49 show that the sum of the numbers of the houses preceding the house number x is equal to the sum of the numbers of the house following x
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the houses in a row are numbered consecutively from 1 to 49
and these numbers are in AP
d =1
a =1
a^n =49
according to the question:
s(x-1 )= s(49) -sx
s (x-1 )+sx=s49
(x-1)/2 +(1+x-x)+x/2*(1+x)=49/2 *50
x(x-1 ) +x(x+1) =49*50
x(x-1+1)=49*50
x(x-1+x+1)=49*50
2x^2=49*50
×^2 =49*25
×=35
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