the human ear can detect continuous sound in the frequency range from 20 Hz to 20,000 Hz. assuming that the speed of sound in air is 330 ms-1 for all frequencies, calculate the wavelength corresponding to the given extreme frequencies of the audible range.
Answers
Answered by
8
Answer:0.0165m
Explanation: Velocity is related to frequency and wavelength as [V=frequency*wavelength]
V=330 m/s
Max. Frequency= 20000 /s
Wavelength= V/frequency = 330/20000 m
Wavelength= 0.0165m
Answered by
6
Answer:
- 16.5 m
- 16.5 mm
Explanation:
Given
- V = 330 m/s
- fₘᵢₙ = 20 Hz
- fₘₐₓ = 20000 Hz
To find
- λₘₐₓ
- λₘᵢₙ
Solution
→ λ = V/f
↣ λₘₐₓ = V/fₘᵢₙ - (I)
↣ λₘᵢₙ = V/fₘₐₓ - (II)
(I)
- 330/20
- 16.5 m
(II)
- 330/20000
- 16.5 × 10⁻³ m
- 16.5 mm
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