Question

the human ear can detect continuous sound in the frequency range from 20 Hz to 20,000 Hz. assuming that the speed of sound in air is 330 ms-1 for all frequencies, calculate the wavelength corresponding to the given extreme frequencies of the audible range. ​

Answer 1

Answer:0.0165m

Explanation: Velocity is related to frequency and wavelength as [V=frequency*wavelength]

V=330 m/s

Max. Frequency= 20000 /s

Wavelength= V/frequency = 330/20000 m

Wavelength= 0.0165m

Answer 2

Answer:

• 16.5 m
• 16.5 mm

Explanation:

Given

• V = 330 m/s
• fₘᵢₙ = 20 Hz
• fₘₐₓ = 20000 Hz

To find

• λₘₐₓ
• λₘᵢₙ

Solution

→ λ = V/f

↣ λₘₐₓ = V/fₘᵢₙ  - (I)

↣ λₘᵢₙ = V/fₘₐₓ  - (II)

(I)

• 330/20
• 16.5 m

(II)

• 330/20000
• 16.5 × 10⁻³ m
• 16.5 mm