The hundreds digit in a 3-digit number is 4 more than the digit at the tens place and 5 more than the digit at
the ones place. If the sum of the three digits is 12, find the number.
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Answer:
It is 462..
Let the ones digit be x.
According to question the tens digit is x+4 as the tens digit Is 4 more than ones.
Similarly the hundreds digit is (x+4)-2 as the hundreds digit is 2 less than tens.
Now sum of all digit is 12.
Thus, (x+4)-2 + x+4 +x =12
- : x+2 +x+4 +x =12
- : 3x +6=12
- : 3x=6
- : x=2
Therefore ones digit Is x=2
Tens digit is x+4= 6
And hundreds digit is (x+4)-2=4
Hence, required ans is 462
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