Question

the hybdisation of central atom of ICl2+

Answer 1

Explanation:

hybridisation no. = 1/2( valance electron on central atom - (+ve charge)+(-ve charge)+ no. of monovalent atom.

Answer 2

Answer:

The hybridisation of central atom of  $ICI^{2+}$is $sp^{3}$.

Explanation:

Hybridisation= $\frac{1}{2} [Valence electrons in central atoms + number of monovalent atoms surrounding the central atom- Positive charge on cation]$

$= \frac{1}{2} [7+2-1]= 4$

The hybridisation of central atom of $ICI^{2+}$is $sp^{3}$.

             

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