Question

The hybrid orbital used by chlorine atom in CIO,
ion is
(1) sp3
(2) sp²
(3) sp
(4) spºd​

Answer 1

Answer:

Explanation:

we can calculate the number of orbitals involved in hybridisation by using the reaction.

Number of orbital involved in hybridisation by using the relation:

Number of orbital involved in hybridisation =12(V+M−C+A)

Where V= number of valence electrons

M= number of monovalent atoms surrounding the atom

C= Charge on cation.

A= Charge on anion.

Number of orbitals involved in hybridisation =12(7+0+0+1)=4

Since 4 orbitals are involved in hybridisation so it is SP3 hybridised.

Hence A is the correct answer.

Answer 2

Answer:

We can calculate the number of orbitals involved in hybridisation by using the reaction.

Number of orbital involved in hybridisation by using the relation:

Number of orbital involved in hybridisation =12(V+M−C+A)

Where V= number of valence electrons

M= number of monovalent atoms surrounding the atom

C= Charge on cation.

A= Charge on anion.

Number of orbitals involved in hybridisation =12(7+0+0+1)=4

Since 4 orbitals are involved in hybridisation so it is SP3 hybridised.