Question

The hybridisation of atomic orbitals of nitrogen in NO+2,NO−3 and NH+4 are

Answer 1

[AIEEE 2011] (1) sp2, sp3, sp (2) sp, sp2, sp3 (3) sp2, sp, sp3 (4) sp, sp3, sp2

(1/2)*(number of lone pair + number of bond pair + respective charge with sign) then if it is 2 then sp and if it is 3 sp2

NO2+NO2+
Number of electron pairs = 2
Number of bond pairs = 2
Number of lone pair = 0
So, the species is linear with sp hybridisation.
NO3−NO3−
Number of electron pairs = 3
Number of bond pairs = 3
Number of lone pair = 0
So, the species is trigonal planar with sp 2 hybridisation
NH4+NH4+
Number of electron pairs = 4
Number of bond pairs = 4
Number of lone pair = 0
So, the species is tetrahedral with sp 3 hybridisation
Thus the answer is (3) sp2 , sp , sp3