Question

The hybridisation of BeCl, in solid state and above 1200 K is respectively
(1) sp3, sp3
(2) sp3, sp2
(3) sp2, sp2
(4) sp3, sp​

Answer 1

Answer:

(D)

Explanation:

Below 1200k, the compound forms coordinate bond at an angle of 45° each. So we see sp3 over there.

Above 1200K, the dimers dissociate, leaving only the linear structure. The linear structure refers to sp hybridization. So go for option (D).

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Answer 2

The hybridisation of BeCl₂, in solid state and above 1200 K is respectively

(4) sp3, sp​

Explanation :

If we look at its structure it is seen that it has Sp hybridization .

This is because : Beryllium only has two electrons and chlorine has 7 electrons and it needs one .Therefore , it shows sp hybridisation .

But in  in real,the solid state of BeCl2 involves donation of a pair of electrons from the chlorine to a neighboring BeCl2 molecule at a 45 degree angle and this forms  a  coordination bonds with the beryllium in each case .

In it  each beryllium forms  four bonds, which require that it be sp3 hybridized. But if we look at single molecule of BeCl₂ solid-state beryllium chloride sp hybridization.