Chemistry, asked by alyg, 6 months ago

the hybridization of a molecule having 16.67 % s character in the hybrid orbital of centre atom will be

a. sp³
b. sp³d
c. sp²
d. sp³d²

Answers

Answered by sanjana3173

1

Answer:

answer is c I think ..............

Explanation:

......

Answered by manaskakkar

0

Answer:

s=16.67 %

P= 100-16.67% =83.33

Now trial and error method

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