Chemistry, asked by manojkumaryadav2827, 10 months ago

The hybridization of central metal ion in brown ring complex is sp3d2 the magnetic moment of the complex is

Answers

Answered by Anonymous
0

Explanation:

Fe is in +1 oxidation state. 3d6 4s1 configuration. Water is a weak ligan.d while NO is a strong liga.nd , so NO will pair one e- (if you draw vbt diagram, you will understand) resulting in sp3d2 hybridisation i.e octahedral geometry.

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Answered by preety89
0

The hybridization of central metal ion in brown ring complex is sp³d² the magnetic moment of the complex is:  

Explanation:

The Brown ring complex is : [Fe(H₂O)₅ (NO) ]⁺²

The oxidation state of Fe is = +1  

The E.C is = 3d⁶4s²

Fe¹⁺= 3d⁶4s¹

In it when the ligands combine : only one pairing occurs .

It is a outer orbital complex .

It is  paramagnetic .

The geometry is " Octahedral ".

The hybridisation is sp³d²

The bonding is shown in figure below :

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