Question

The hybridization of the central carbon in ch3c≡n and the bond angle ccn are sp2, 180° sp, 180° sp2, 120°. sp3, 109°

Answer 1

Concept introduction:

To find hybridization of a molecule we find the steric number(S.N) which is summation of number of σ bonds and number of lone pairs.

S.N = $2$ ⇒ sp

S.N = $3$ ⇒ sp$2$

S.N = $4$ ⇒ sp$3$

Explanation:

Given that, we have compound CH₃C≡N.

We have to find, the hybridization of middle C in CH₃C≡N compound.

According to the question,

CH₃C≡N has $2$ σ bonds and no lone pair

∴ S.N = $2$ + $0$ = $2$

Hence hybridization of CH₃C≡N is sp and compound with sp hybridization have bond angle $180$°.

Final Answer: Hybridization of CH₃C≡N is sp and bond angle is $180$°.

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