Question

the hydrated salt Na2CO3.nH2O undergoes 63% loss in mass on heating and becomes anhydrous. find vlue of n?

Answer 1

let mass of the salt is w then
w = 106 + 18n .................(1)
after heating 
37w / 100 = 106
w = 106*100 / 37 
putting value of w in equation (1)
106*100 / 37 = 106 + 18n
106* 63 / 37 = 18n 
n = 10.02 
hence n = 10

Answer 2

Answer:

the answer will be 10

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