Question

the hydrated salt Na2SO4. 10H2O undergoes X%loss in weight on heating and become anhydrous. the value of X will be

Answer 1

Given reaction: Na2SO4.10H2O——>Na2SO4 + 10H2O
Here moles of Na2SO4.10H2O = 1 mole
Because, weight of substance = no. of moles* molecular weight
Therefore, weight of substance = 1*(46+32+64+180)
= 322g
Similarly, weight of anhydrous Na2SO4 = 180g

Therefore, percentage loss = [(320-180)/322]*100
=55.90%

Answer 2

Answer:

56%

Explanation:

molecular mass of Na2So4=322

on heating the Na2So410H2o it becomes anhydrous that means 10H2o molecules seprated

molecular mass of10H2o =180

%loss = 180/322×100=55.9%=56%