The hydrated salt Na2SO4.nEo undergoes 55.9% loss in weight on heating and becomes anhydrous. The value of n will be
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Na2SO4.nH2O
The molecular mass = 46 + 32 + 64 + 18n = 142+18n
The mass of anhydrous salt = 142
Given 18n x 100/ (142+18n) = 55.9
1800n = 7937.8 + 1006.2 n
n = 7937.8/793.8 = 10
Therefore the compound is Na2SO4.10H2O
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