Question

The hydrogen electrode is dipped in a solution
of pH = 3 at 25°C. The potential of the cell
would be
(use value of 2.303RT/F=0.059v)

= 0.059 V
(a) 0.059 V
(c) 0.178 V
(b) 0.088 V
(d)-0.177 V​

Answer 1

Answer:

Option D -0.177 V,

Explanation:

⇒pH=3 ,

⇒[H3O^+]=10^-pH=10^-3M,

⇒E el=E el^0-0.059/n log PH2/[H^+]^2,

⇒E el=0-0.059/n log 1/(10^-3)^2,

⇒E el=-0.177 V.

Hope it helps you.