Chemistry, asked by Abhishrk2782, 1 year ago

The hydrolysis of methyl acetate in aqueous solution has been studied by titrating the liberated acetic acid against sodium hydroxide the concentration of acid different time is given below

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Answered by abhi178
14
your question is incomplete. A complete question is shown in figure.


solution :- For Pseudo first order reaction, The reaction should be first order with respect to ester, when concentration of water remains constant. e.g., [H2O] remains constant.

hence, rate constant k for pseudo first order reaction is given by, k=\frac{2.303}{t}log\frac{C_0}{C} , where k = k'[H20]

here, C_0 initial concentration, C is final concentration and t is taken time.

from above data, it is clear that, k'[H2O] is constant and is equal to 2.004 × 10^-3/min. hence, it depends on Pseudo first order reaction and we can determine k from k'[H2O]
k' × 55mol/L = 2.004 × 10^-3
so, k' = 3.64 × 10^-5 mol/L/min.
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