the hydroxide soluble in excess of ammonium hydroxide is
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In excess of NH4OH,Cu2+ forms soluble complex [Cu(NH3)4]SO4.
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Explanation:
The metal hydroxide which is soluble in excess of ammonium hydroxide is Cu(OH)
2
. It forms soluble complex tetramminecupric hydroxide [Cu(NH
3
)
4
](OH)
2
.
Cu(OH)
2
+4NH
4
OH→[Cu(NH
3
)
4
](OH)
2
+4H
2
O
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