Question

The hypotenuse of a Isoscles right angle triangle is root 32 . What is its area ?

Answer 1

hypotenuse

$= \sqrt{32}$

$= \sqrt{16 + 16}$

$= \sqrt{ {(4)}^{2} + {(4)}^{2} }$

Thus, the other two perpendicular sides are of length 4 units each.

Thus,

Area

$= \dfrac{1}{ \cancel2} \times \cancel4 { \ }^{2} \times 4$

$= 2 \times 4$

$= 8$ sq. units