the hypotenuse of a right angle is 17 cm long.If one of the remaining two sides is of length 8 cm,find the length of third side?
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c2=a2+b2
(17)2=(8)2+B2
289-64=B2
225=B2
B=√225
B=15 (ANS)
(17)2=(8)2+B2
289-64=B2
225=B2
B=√225
B=15 (ANS)
subhamkishoresinha:
prateek your answer is correct but i want answer by pythagorus theorem
Answered by
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given, hypotenuse =17cm
let A =8 cm be the length of first leg and
B be the length of second leg of triangle
then, 17^2 -8^2=B^2
B^2=289-64=225
B=15cm
let A =8 cm be the length of first leg and
B be the length of second leg of triangle
then, 17^2 -8^2=B^2
B^2=289-64=225
B=15cm
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