The hypotenuse of a right angle triangle is 20 centimetre the difference between its other two sides is 4 centimetre find the length of its side
Answers
Answered by
2
Answer:
one of the side is 12 cm while the other side is 16 cm.
Step-by-step explanation:
Let one of the sides be x then another side is 4 + x:
Applying Pythagoras theorem, we get::
(20)² = (x)² + (x + 4)²
400 = x² + x² + 8x + 16
400 = 2x² + 8x + 16
2x² + 8x - 384 = 0
x² + 4x - 192 = 0
x² + 16x - 12x - 192 = 0
x(x + 16) - 12(x + 16) = 0
(x - 12)(x + 16) = 0
x= 12 or x = -16
(But length can't be negative).
Hence, one of the side is 12 cm while the other side is:
one side = 4+x
other side = 4 + 12
= 16 cm.
So other side is 16 cm.
Verification::
(12)² + (16)² = 144 + 256 = 400
Hypotenuse = √400 = 20 cm
I hope it will helps you friend
Answered by
1
Let the sides be x and x+4 .
According to Pythagoras theorem,
20*20=(x*x)+(x+4)*(x+4)
400= x^2 + x^2+8x+16
2x^2+8x-384=0
Taking 2 common,
x^2+4x-192=0
x^2+16x-12x-196=0
x(x+16)-12(x+16)=0
(x+16)(x-12)=0
Therefore, x=12cm
and other side=x+4=12+4=16cm
According to Pythagoras theorem,
20*20=(x*x)+(x+4)*(x+4)
400= x^2 + x^2+8x+16
2x^2+8x-384=0
Taking 2 common,
x^2+4x-192=0
x^2+16x-12x-196=0
x(x+16)-12(x+16)=0
(x+16)(x-12)=0
Therefore, x=12cm
and other side=x+4=12+4=16cm
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