The hypotenuse of a right angle triangle is 25cm. if one of the side is 7cm, find the length of the other side
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Answered by
4
Let other side be x
h²=7²+x²
25²=7²+x²
625-49=x²
24=x
24cm length is of other side
To verify
25²=24²+7²
625=576+49
625=625
h²=7²+x²
25²=7²+x²
625-49=x²
24=x
24cm length is of other side
To verify
25²=24²+7²
625=576+49
625=625
Answered by
0
Answer:By Pythagoras theorem( Hypotenuse)2=(Side one)2+(side two )2
Therefore , 25×25=7×7+side two sq.
so, 625=49+side two sq.
so, 625-49 = side two sq.
576= side two sq.
taking sq . root on both sides
√576=24 cm .
So, another side is 24 cm.
Therefore , 25×25=7×7+side two sq.
so, 625=49+side two sq.
so, 625-49 = side two sq.
576= side two sq.
taking sq . root on both sides
√576=24 cm .
So, another side is 24 cm.
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