Question

The hypotenuse of a right angle triangle is 29.0 centimeters the length of one it’s legs is 20.0 what is the length of the other leg

Answer 1

Answer:

29²=20²+AC ²

841=400+Ac²

Ac²=841-400

Ac²=441

Taking sqaure root

AC=21

if helpful plz add brainliest

Answer 2

Answer:

21cm

Explanation:

Let the other leg be 'x'

Given

The hypotenuse, h = 29 cm

One leg p = 20 cm

According to Pythagorus theorem

$hypotenuse {}^{2} = {x}^{2} + p {}^{2}$

$= > 29 {}^{2} = {x}^{2} + 20 {}^{2}$

$= > {x}^{2} = {29}^{2} - 20 {}^{2}$

$= > {x}^{2} = (29 + 20)(29 - 20)$

$= > {x}^{2} = 49 \times 9$

$= > x = \sqrt{49 \times 9}$

$= > x = \sqrt{ {7}^{2} \times {3}^{2} }$

$= > x = 7 \times 3$

$so \: \: \: x = 21 \: cm$

Hence the other leg is 21cm