Question

The hypotenuse of a right angle triangle is 3 cm more than twice its shortest side if one third side is 1 cm less than the hypotenus , find the sides of the triangle

Answer 1

Answer:

Step-by-step explanation:

h=3+2b

b=h-3/2 --------1

h=p+1

h-1=p  --------2

$h^{2}$=$p^{2}$+$b^{2}$

$h^{2}$ = $(h-1)^{2}$ + $(h-3/2)^{2}$

$h^{2}$ =$h^{2}$ - 2h +1 + $h^{2}$ - 3h + 9/4

$h^{2}$ - $h^{2}$  - $h^{2}$ = -2h - 3h +1 +9/4

- $h^{2}$ = -5h + 11/4

$h^{2}$ = 5h - 11/4

h = $\sqrt{5h-11/4}$

Answer 2

Step-by-step explanation:

h=3+2b

b=h-3/2 --------1

h=p+1

h-1=p --------2

h^{2}h

2

=p^{2}p

2

+b^{2}b

2

h^{2}h

2

= (h-1)^{2}(h−1)

2

+ (h-3/2)^{2}(h−3/2)

2

h^{2}h

2

=h^{2}h

2

- 2h +1 + h^{2}h

2

- 3h + 9/4

h^{2}h

2

- h^{2}h

2

- h^{2}h

2

= -2h - 3h +1 +9/4

- h^{2}h

2

= -5h + 11/4

h^{2}h

2

= 5h - 11/4

h = \sqrt{5h-11/4}

5h−11/4

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