Question

the hypotenuse of a right angle triangle is 4m less than thrice the length of the shortest side . Third side is 2m less than the hypotenuse. find the sides of the triangle​

Answer 1

Step-by-step explanation:

AB=3x-6

BC=3x

CA=3x-4

by Pythagoras theorem,

CA²=AB²+BC²

(3x-4)²=(3x-6)²+(3x)

9x²+16-24x=9x²+36-36x+3x

9x²-24x+16=9x²-33x+36

33x-24x=36-16

9x=20

---------------------

x=20/9

3(20/9)

20/3

--------------------

3(20/9)-6

20/3-6

20-18/3

2/3

----------------------

3(20/9)-4

20/3-4

20-12/3

8/3

-----------------

AB=2/3

BC=20/3

CA=8/3

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Answer 2

Answer:

Step-by-step explanation:let ABC be right angled triangle.

BC=xm

AC=3x-4m

AB=3x-6m

By Pythagoras theorem

AC^2=AB^2+BC^2

(3x-4)^2=(3x-6)^2+(x)^2

9x^2-24x+16=9x^2-36x+36+x^2

-x^2-24x+36x+16-36=0

-x^2+12x-20=0

x^2-12x+20=0

X^2-10x-2x+20=0

(X-10) (x-2)=0

X=10 or x=2

AC=(3x-4)

= 3(10)-4

=30-4

=26m

AB=(3x-6)

=3(10)-6

=30-6

=24m