The hypotenuse of a right angle triangle is 5m.if one of its side is 4m.find the lengh of the other side
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using Pythagoras theorum
hypt^2=base^2+height^2
5^2=4^2+height^2
25=16+height^2
height^2=25-16
height^2=9
height=√9=3
the lenght of other side is 3 cm.
hypt^2=base^2+height^2
5^2=4^2+height^2
25=16+height^2
height^2=25-16
height^2=9
height=√9=3
the lenght of other side is 3 cm.
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