The hypotenuse of a right-angle triangle is 6 cm more than twice the shortest side.If the third side 2 cm less than the hypotenuse,what are the side's of triangle in cm?
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Let the hypotenuse be x.
x - 6 /2 , x -2 are the other sides.
( x/2 -3 )² + (x-2)² = x²
x²/4 + 9 -3x + x²+4 - 4x = x²
x²/4 -7x +13 = 0
x²-28x + 52 = 0 .
x² - 2x-26x + 52x = 0
x( x-2)-26(x-2) = 0
x = 2 ,26 .
If 2 is hypotenuse, Then other sides, 2 - 6/2 , 2 -2 .These measures are not possible so.
26 is the hypotenuse. Other sides are 10 , 24 respectively.
x - 6 /2 , x -2 are the other sides.
( x/2 -3 )² + (x-2)² = x²
x²/4 + 9 -3x + x²+4 - 4x = x²
x²/4 -7x +13 = 0
x²-28x + 52 = 0 .
x² - 2x-26x + 52x = 0
x( x-2)-26(x-2) = 0
x = 2 ,26 .
If 2 is hypotenuse, Then other sides, 2 - 6/2 , 2 -2 .These measures are not possible so.
26 is the hypotenuse. Other sides are 10 , 24 respectively.
Ankitsuraj:
no you r wrong . let shortest side be x
We can assume anything ,what we require is the correct solution
yes yes yes
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