Question

the hypotenuse of a right angle triangle is 65 centimetre and its base in 60. cm find the length of perpendicular and the area of triangle​

Answer 1

Answer:

Step-by-step explanation:

hello frnd......

here is ur answer .......

... according to the question,

we can solve the problem by phythagoras therom

in this (hypotenuse) square = side square+ side square.

as per the question,

hypotenuse =65

and side =60

65 square = 60 square + side square

4225=3600+ side square

side square=4225-3600

side square= 625

side =✓625

side = 25 cm.

side of a triangle = 25 cm

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Answer 2

Answer:

In ABC

AB is the height of a triangle

AB= ?

BC is the base of triangle

BC=60cm

AC is the hypotenuse of a triangle

AC=65cm

find the length of perpendicular

AB=?

By Pythagorean theorem

${ac}^{2} = {ab}^{2} + {bc}^{2} \\ {65}^{2} = {ab}^{2} + {60}^{2} \\ 4225 = {ab}^{2} + 3600 \\ 4225 - 3600 = {ab}^{2} \\ 625 = {ab}^{2} \\ taking \: squareroot \: \\ 25 = ab$

length of perpendicular is 25 cm

AB=25 cm

Now,

area of triangle =?

Area of triangle = height *base /2

=25*60/2

=750cm