Question

The hypotenuse of a right angled isosceles triangle is 16 root 2 m, find its area

Answer 1

here,
on applying Pythagoras theorem, we get

2a^2= 512
a=16
now, area of a right triangle equals to 1/2×b×h
= 1/2×16×16
= 128 m^2

Answer 2

Area of triangle is 128 m^2

Hypotenuse of triangle=16 root 2

Let equal sides of isosceles triangle= x m

According to Pythagoras theorem we have:--

(Hypotenuse)^2=(Base)^2+(Height)^2

(16root2)^2=x^2+x^2

512=2x^2

x=16 m

Area of triangle=1/2*base*height

Area=1/2*16*16=8*16=128 m^2

So area of right angled isosceles triangle is 128 m^2.