Question

the hypotenuse of a right angled isosceles triangle is 16root2m find its area​

Answer 1

(a^2+a^2)^0.5=16(2)^0.5

Hence (2)^0.5×a=16(2)^0.5

Hence a = the side =16

Hence the area will be 1/2×base×height

=1/2×16×16=128