The hypotenuse of a right angled triangle is 13 cm. and the difference of the other two sides is 7 cm. Find the perimeter of the triangle
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Answered by
31
Answer:
30 cm
Step-by-step explanation:
We have,
Hypotenuse of a right angled triangle = 13 cm.
Let the length of the first side be 'x' cm.
Given that difference between the other two sides is 7 cm.
⇒ x² + (x + 7)² = 13²
⇒ x² + x² + 49 + 14x = 169
⇒ 2x² + 14x - 120 = 0
⇒ x² + 7x - 60 = 0
⇒ x² + 12x - 5x - 60 = 0
⇒ x(x + 12) - 5(x + 12) = 0
⇒ (x - 5)(x + 12) = 0
⇒ x = 5.
Then:
x + 7 = 12 cm.
∴ Perimeter of the triangle = 30 cm
Hope it helps!
Answered by
14
x² + (x + 7)² = 13²
⇒ x² + x² + 49 + 14x = 169
⇒ 2x² + 14x - 120 = 0
⇒ x² + 7x - 60 = 0
⇒ x² + 12x - 5x - 60 = 0
⇒ x(x + 12) - 5(x + 12) = 0
⇒ (x - 5)(x + 12) = 0
⇒ x = 5.
Then:
x + 7 = 12 cm.
∴ Perimeter of the triangle = 30 cm
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