Math, asked by nandhithanb, 7 hours ago

The hypotenuse of a right angled triangle is 15 cm. Taking the perpendicular sides as x, y write the
relation connecting the sides ?
If the area is 30cm2
find the length of its perpendicular sides ?

Answers

Answered by mohdaquib123786
0

Answer:

your answer is 45=36. subwoofer area side

Answered by Manmohan04
0

Given,

Hypotenuse of right angles triangle \[ = 15cm\]

Other sides are x and y.

Area of triangle \[ = 30c{m^2}\]

Solution,

Relation connecting the sides ?

\[\begin{array}{l}{x^2} + {y^2} = {15^2}\\ \Rightarrow {x^2} + {y^2} = 225\end{array}\]--------(1)

If the area is \[30c{m^2}\]  find the length of its perpendicular sides ?

\[\begin{array}{l}\frac{1}{2}xy = 30\\ \Rightarrow xy = 60\end{array}\]----------(2)

Apply equation 1 and 2,

\[\begin{array}{l}{\left( {x + y} \right)^2} = {x^2} + {y^2} + 2xy\\ \Rightarrow {\left( {x + y} \right)^2} = 225 + 2 \times 60\\ \Rightarrow {\left( {x + y} \right)^2} = 345\\ \Rightarrow x + y = 18.57\end{array}\]-----------(3)

\[\begin{array}{l}{\left( {x - y} \right)^2} = {x^2} + {y^2} - 2xy\\ \Rightarrow {\left( {x - y} \right)^2} = 225 - 2 \times 60\\ \Rightarrow {\left( {x - y} \right)^2} = 105\\ \Rightarrow x - y = 10.24\end{array}\]------------(4)

Solve equation 3 and 4,

\[\begin{array}{l}x = 14.41cm\\y = 4.163cm\end{array}\]

Hence the length of perpendicular side is \[14.41cm\].

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