Question

The hypotenuse of a right angled triangle is 17 cm long and the difference between the other two sides is 7 cm. Find the lengths of two unknown sides.

Answer 1

HEY FRIEND

HERE IS YOUR ANSWER

GIVEN :

HYPOTENUSE=17 cm

DIFFERENCE =7cm

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Let the other two sides be x and x-7

WE KNOW THAT

H²=P²+B²

17²=x²+(x-7)²

[USING (a-b)²=a²+b²-2ab]

289=x²+x²+49-14x

289-49=2x²-14x

240=2x²-14x

2x²-14x-240=0

2(x²-7x-120)=0

x²-7x-120=0

x²-15x+8x-120=0

x(x-15)+8(x-15)=0

(x+8)(x-15)=0

x+8=0

x= -8(rejected)

x-15=0

x=15

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LENGTH OF OTHER TWO SIDES

x=15cm

x-7=15-7=8cm

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SO THE LENGTH OF OTHER TWO SIDES ARE 15cm AND 8cm.

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HOPE THIS HELPS YOU ☺

Answer 2

HERE'S your complete ans....