Question

the hypotenuse of a right angled triangle is 25cm and perpendicular is 9cm find its base​

Answer 1

hypotenuse=25cm

perpendicular=7cm

base=?

According to Pythagoras theorem

(Hypotenuse) square=(Base) square + (Perpendicular) square

25 square=(Base) square +7square

625= (Base) square +49

(Base) square=625-49

Base √576

Base=24cm

PLS MARK BRAINLIEST

Answer 2

Answer:

$given \: hypotenuse = 25 \: height \: is \: 9$

$using \: pytagores \: therom$

${25}^{2} = {9}^{2} + {base}^{2}$

$625 = 81 + {b}^{2}$

$625 - 81 = {b}^{2}$

${b}^{2} = 625 - 81$

${b}^{2} = 544$

$b = 23.32$