the hypotenuse of a right angled triangle is 29 cm the difference between the other two sides is 1 cm find the other two sides
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Let one side be xcm.Since the difference between the two sides is 1cm
∴ the other side=x+1cm
As the given triangle is a right angled triangle with hypotenuse =29cm
By using pythagoras theorem, we get
x²+(x+1)²=29²
x²+x²+1+2x=841
2x²+2x+1=841
2x²+2x=841-1
2x²+2x=840
2(x²+x)=840
x²+x=840/2
x²+x=420
x²+ x - 420=0
A = 1
B = 1
C = -420
putting in Quadratic formula
after solution the value of x= 20, (x+1)= 21
so we neglect negative value therefore x= 20
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