the hypotenuse of a right angled triangle is a 25 if one side is 5m more than other side find its area
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Let one side be x.
Hence second one is (x+5).
By Pythagoras Theorem,
=) x^2 + (x+5)^2 = 25^2
=) x^2 + x^2 + 10x + 25 = 625
=) 2x^2 + 10x = 600
=) 2(x^2 + 5x) = 600
=) x^2 + 5x = 300
=) x^2 + 5x - 300 = 0
=) x^2 + 20x - 15x - 300 = 0
=) x(x+20) - 15(x+20) = 0
=) (x-15)(x+20) = 0
Hence x = 15 and - 20.
Take positive no. as a zero because it's understandable.
Hence x = 15 and other side be 15+5 = 20m
Area = 1/2 * b*h
= 1/2 * 15 * 20 m^2
= 150m^2.
Hope it's helpful to u.
Hence second one is (x+5).
By Pythagoras Theorem,
=) x^2 + (x+5)^2 = 25^2
=) x^2 + x^2 + 10x + 25 = 625
=) 2x^2 + 10x = 600
=) 2(x^2 + 5x) = 600
=) x^2 + 5x = 300
=) x^2 + 5x - 300 = 0
=) x^2 + 20x - 15x - 300 = 0
=) x(x+20) - 15(x+20) = 0
=) (x-15)(x+20) = 0
Hence x = 15 and - 20.
Take positive no. as a zero because it's understandable.
Hence x = 15 and other side be 15+5 = 20m
Area = 1/2 * b*h
= 1/2 * 15 * 20 m^2
= 150m^2.
Hope it's helpful to u.
Answered by
0
Do the area will be 150 m2
Hope this was helpful
Then please mark my answer as brainliest
Hope this was helpful
Then please mark my answer as brainliest
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