The hypotenuse of a right triangle is 1m less than twicethe shortest side.If the third side is 1m more than the shortest side.Find the sides of the triangle
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Let the length of shortest side=x
Hypotenuse =2x-1
Third side=x+1
Hypotenuse square = sum of the squares of other two sides
(2x-1)^2=x^2+(x+1)^2
4x^2-4x+1=x^2+x^2+2x+1
4x^2-2x^2-4x+1-2x-1=0
2x^2-6x=0
2x(x-3)=0
x=0 or x-3=0
Therefore
x=3
Shortest side=x=3
Hypotenuse=2x-1=2*3-1=5
Third side= x+1=3+1=4
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