Question

The hypotenuse of a right triangle is
25 cm. If one of the side is 7 cm, find the
length of the other side.explain with solution​

Answer 1

$\bf{\red{Question}}$

• The hypotenuse of a right triangle is 25 cm. If one of the side is 7 cm, find the length of the other side.

$\bf{\red{Answer}}$

• The Perpendicular of triangle is 24 cm.

$\bf{\red{To\:find:-}}$

• Third side of triangle

$\bf{\red{Solution:-}}$

• Hypotenuse (h) = 25 cm
• Base (b) = 7 cm
• Perpendicular (p) = ?

According to Pythagoras theorem,

$\large{ \pink{ \underline{ \underline{ \purple{ \mathfrak{ {hypotenuse}^{2} = {base}^{2} + {perpendicular}^{2} }}}}}}$

According to question,

$\large{ \tt : \implies \: \: \: \: \: \: {25}^{2} = {7}^{2} + {p}^{2} }$

$\large{ \tt : \implies \: \: \: \: \: {p}^{2} = {25}^{2} - {7}^{2} }$

$\large{ \tt : \implies \: \: \: \: \: {p}^{2} = 625 - 49}$

$\large{ \tt : \implies \: \: \: \: \: {p}^{2} = 576}$

$\large{ \tt : \implies \: \: \: \: \: p = \sqrt{576} }$

$\large{ \tt : \implies \: \: \: \: \: p = 24 \: cm}$

The Perpendicular of triangle is 24 cm.