Question

The hypotenuse of a right triangle is 26 cm long. if one of the remaining two sides is 10 cm long, find the length of the other side​

Answer 1

According to Pythagoras theorem

$p {}^{2} + h {}^{2} = b {}^{2}$

$h {}^{2} = 26 {}^{2} \\ p {}^{2} = 10 {}^{2}$

$let \: the \: other \: side \: be \: x {}^{2}$

So ,

$h {}^{2} + p {}^{2} = x {}^{2}$

$26 {}^{2} + 10 {}^{2} = x {}^{2}$

$676 + 100 = x {}^{2}$

$776 = x {}^{2}$

$x = \sqrt{776}$

$x = 27.85$

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Answer 2

Given ,

Hypotenuse of a right angled triangle is 26 and one of the remaining sides of Δ is 10 cm

Let , the unknown side be x

We know that , by phythagores theorem

$\large \mathtt{ \fbox{ {(h)}^{2} = {(b)}^{2} + {(p)}^{2}} }$

Thus ,

(26)² = (10)² + (p)²

676 = 100 + (p)²

(p)² = 576

p = ± 24 cm

Since ,the length can't be negative

Hence , the length of other side of Δ is 24 cm